Solution:

Joining the points A, B and C we get a square ABCD.

Solution:

The equation of the line parallel to the Y-axis at a distance of 7 units from it to its left is x = − 7.

Solution:

The equation of the line parallel to the X-axis at a distance of 5 units from it and below the X-axis is y = − 5.

Solution:

The equation of the line parallel to the Y-axis passing through the point Q(− 3, − 2) is x = − 3.

Solution:

The distance between the X-axis and the line y = − 4 is 4 units.

Solution:

The equation of a line parallel to the X-axis is in the form y = b.

The equation of a line parallel to the Y-axis is in the form x = a.

1. x = 3
   → Parallel to the Y-axis
2. y − 2 = 0
   ∴ y = 2
   → Parallel to the X-axis
3. x + 6 = 0
   ∴ x = − 6
   → Parallel to the Y-axis
4. y = − 5
   → Parallel to the X-axis

Solution:

The line intersects the X-axis in the point (5, 0).

The line intersects the Y-axis in the point (0, 5).

Solution:

1.  x + 4 = 0
   ∴ x = − 4
2.  y − 1 = 0
   ∴ y = 1
3.  2x + 3 = 0
   ∴ 2x = − 3
   ∴ x = − \(\frac{3}{2}\)
4.  3y − 15 = 0
   ∴ 3y = 15
   ∴ y = \(\frac{15}{3}\)
   ∴ y = 5

The co-ordinates of the points of intersection of these lines are: (− 4, 5), (− 1.5, 5), (− 1.5, 1) and (− 4, 1).

Solution:

Now, prepare a table as shown below:

Now, prepare a table as shown below:

Now, prepare a table as shown below: